Gearing accuracy of manufacturing

Types of gear drives Peripheral speed V, m/sec
under 5 5 - 8 8 – 12.5 over 12.5
Straight spur gears        
Helical spur gears        
Straight bevel gears     - -
Spiral bevel gears        

Table 3.6

Dynamic load factor KHV

Gearing accuracy of manufacturing Tooth surface hardness, BHN Peripheral speed V, m/sec
           
  up to 350 over 350 1.04/1.02 1.03/1.00 1.07/1.03 1.05/1.01 1.14/1.05 1.09/1.02 1.21/1.06 1.14/1.03 1.29/1.07 1.19/1.03 1.36/1.08 1.24/1.04
  up to 350 over 350 1.04/1.01 1.03/1.01 1.08/1.02 1.06/1.01 1.16/1.04 1.10/1.02 1.24/1.06 1.16/1.03 1.32/1.07 1.22/1.04 1.40/1.08 1.26/1.05
  up to 350 over 350 1.05/1.01 1.04/1.01 1.10/1.03 1.07/1.01 1.20/1.05 1.13/1.02 1.30/1.07 1.20/1.03 1.40/1.09 1.26/1.04 1.50/1.12 1.32/1.05

Note: The figures in the numerators refer to straight spur gears and those in the denominators, to helical spur gears.

Obtained value of σ H should correspond to the following condition:

σ H = (0.8…1.1)∙[σ H ].

Otherwise it is necessary to change the center distance a w and recalculate the gearing.

In our case 412,4≤488,78≤567. Condition is satisfied.

3.14. Determine the maximum bending stress

where Kb b is the load concentration factor that is determined by table 3.7; Kbv is the dynamic load factor determined from table 3.8; Yb is the tooth form factor that is determined by means of table 3.9 depending upon the number of teeth of the gear for the case when the offset factor x =0

If obtained magnitude of σ b >[σ b ] it is necessary to increase the module.

Table 3.7

Approximate values of Kb β

Gear arrangement with respect to bearings Tooth surface hardness, BHN
0.2 0.4 0.6 0.8 1.2 1.6
On cantilevers, ball bearings up to 350 over 350 1.16 1.33 1.37 1.70 1.64 - - - - - - -
On cantilevers, roller bearings up to 350 over 350 1.10 1.20 1.22 1.44 1.38 1.71 1.57 - - - - -
Symmetrical up to 350 over 350 1.01 1.02 1.03 1.04 1.05 1.08 1.07 1.14 1.14 1.30 1.26 -
Nonsymmetrical up to 350 over 350 1.05 1.09 1.10 1.18 1.17 1.30 1.25 1.43 1.42 1.73 1.61 -

Table 3.8

Dynamic load factor KbV

Gearing accuracy of manufacturing Tooth surface hardness, BHN Peripheral speed V, m/sec
           
  up to 350 over 350 1.08/1.03 1.03/1.01 1.16/1.06 1.05/1.02 1.33/1.11 1.09/1.03 1.50/1.16 1.13/1.05 1.62/1.22 1.17/1.07 1.80/1.27 1.22/1.08
  up to 350 over 350 1.10/1.03 1.04/1.01 1.20/1.06 1.06/1.02 1.38/1.11 1.12/1.03 1.58/1.17 1.16/1.05 1.78/1.23 1.21/1.05 1.96/1.29 1.26/1.08
  up to 350 over 350 1.13/1.04 1.04/1.01 1.28/1.07 1.07/1.02 1.50/1.14 1.14/1.04 1.72/1.21 1.21/1.06 1.98/1.28 1.27/1.08 1.25/1.35 1.34/1.09

Note: The figures in the numerators refer to straight spur gears and those in the denominators, to helical spur gears.

Table 3.9

Tooth form factor Yb

z or zv                            
Y b 4.27 4.07 3.98 3.92 3.88 3.81 3.8 3.75 3.7 3.66 3.65 3.62 3.61 3.6

4. ANALYSIS OF THE HELICAL SPUR GEARS FOR STRENGTH

4.1. Determine the center distance of the helical spur gears

,

where u is the velocity ratio of the gearing; Tg is the torque at the gear shaft in N·mm; [ σH ] is the allowable contact stress in MPa; Etr is the transformed modulus of elasticity in MPa; K is the load concentration factor; ψba= bg/aw is the gear face width factor.

Transformed modulus of elasticity Etr is determined as

,

where Ep and Eg are correspondingly modules of elasticity of pinion and gear materials. Since the pinion and the gear are made of steel we can make the conclusion that Etr = Ep = Eg = 2.1·105 MPa.

Load concentration factor K is determined by means of table 3.2 depending on disposition of toothed wheels with respect to bearings and factor ψbd= bg/dp. Since bg and dp were not determined we find this factor by the following formula

,

where gear face width factor ψba is determined from table 3.1 depending on the disposition of the gear relative to bearings taking into account that the value of this factor should correspond to standard. The greater ψba the less overall dimensions of the gearing. That is why we select the greater magnitude of ψba.

Obtained magnitude of aw should be rounded off to the nearest greater side according to the series given in table 3.3.

In our case: Tg = 464.3 N·m; Tp = 119.67 N·m; u = 4;
H] = 515,5 MPa;Etr = 2.1·105 MPa;[σb] = 255.6 MPa, symmetrical disposition of gears with respect to supports.

From table 3.1 we take ψba = 0.5; then ,

From table 3.2 we take K = 1.07 (for symmetrical gear arrangement and tooth surface hardness up to 350).

Than

Round off obtained magnitude of to the nearest greater side according to table 3.3. That is why we take aw = 140 mm for further calculations.

4.2. Determine the nominal pitch circle diameter of the gear

.

4.3. Determine the face width of the gear

bg = ψba·aw = 0.5·140 = 70 mm.

4.4. Determine the normal module according to the strength condition for bending

,

where Km is taken as 5.8 for helical spur gears.

Obtained magnitude of the module should be rounded off to the greater side according to the standard series given in table 3.4. It is necessary to note that for general-purpose speed reducers the minimum value of the module is mmin = 2 mm, in our case

,

we take mn = 2 mm for further calculations.

4.5. Determine the helix angle

.

For helical spur gears this angle should be ranged from 8 to 18˚. Otherwise, it is necessary to change the normal module mn. As in our case that is less than , that’s why we take mn= 3mm, than

4.6. Determine the total number of teeth

.

Obtained value of zΣ should be rounded off to the nearest integer numeral, assume zΣ = 92.

4.7. Specify the helix angle according to the integer number of zΣ

Obtained value of this angle is ranged from 8 to 18˚. Condition is satisfied.

4.8. Determine the number of teeth of the pinion

,

where for helical spur gears zmin=17· .

Obtained value of zp should be rounded off to the nearest integer numeral. If zp <17· it is necessary to decrease the module or to use nonstandard toothed wheels.

In our case

4.9. Determine the number of teeth of the gear

.

4.10. Specify the velocity ratio of the gearing

uact= .

The error ε = should be less or equal to 4%. Otherwise the number of teeth zp, zg and zΣ must be rounded off to the other side.

In our case condition is satisfied, since

;

4.11. Determine the nominal pitch circle diameters for the pinion and the gear

,

dg = 2· a w - dp = 2·140 – 54.78 = 225.22 mm.

4.12. Determine the addendum circle diameters for the pinion and the gear

,

.

4.13. Determine the dedendum circle diameters for the pinion and the gear

,

.

4.14. Determine forces that act in the engagement of the helical spur gears:

- turning force ;

- radial force ;

- axial force

where αw=20˚ is the pressure angle for the pitch circle.

4.15. Determine the maximum contact stress that develops in the contact zone of teeth

,

where Z takes into account rising the contact strength of the helical spur gears in comparison with the straight spur gears; Tp is the torque at the pinion shaft in N·mm; KH is the design load factor that is determined as

,

where K is the load concentration factor; KHV is the dynamic load factor.

The load concentration factor K is specified by table 3.2 depending upon .

In order to determine KHV it is necessary to find the peripheral speed Vg of the gear

where ωg is the angular velocity of the gear and the gearing accuracy of manufacturing (table 3.5),.

The dynamic load factor KHV is determined by table 3.6.

Factor Z is determined in the following way

,

where K takes into account non-uniform load distribution between several pairs of teeth; εα is the contact ratio.

Table 4.1

Factors K, K that take into account non-uniform load distribution between some pairs

Peripheral speed V, m/sec Accuracy of manufacturing K K
To 5   1.03 1.07
    1.07 1.22
    1.13 1.35
From 5 to 10   1.05 1.2
    1.10 1.3
From 10 to 15   1.08 1.25
    1.15 1.40

K depends upon the accuracy of manufacturing and the peripheral speed and is determined according to table 4.1.

Contact ratio εα is found by the following formula

.

Obtained value of σH should correspond to the following condition:

σH = (0.8…1.1)·[σH ].

Otherwise it is necessary to change the center distance aw and recalculate the gearing.

In our case: ; K = 1.07;

;

Accuracy of manufacturing gear drive is 9; KH = 1.07·1.01= 1.0807;

; K = 1.13;

;

;

Obtained value of σ H should correspond to the following condition:

σ H = (0.8…1.1)∙[σ H ].

Otherwise it is necessary to change the center distance a w and recalculate the gearing.

In our case 412,4≤483,287≤567. Condition is satisfied.

4.16. Determine the maximum bending stress

,

where K is the load concentration factor that is determined by table 3.7; Kbv is the dynamic load factor determined from table 3.8; Yb is the tooth form factor that is determined by means of table 3.9 depending on the number of teeth of the equivalent straight spur gear for the case when the shift factor x=0.

Factor Z is the analogy of Z and is determined as

,

where K is chosen from table 4.1; is the correction factor.

If obtained magnitude of σb > [σb] it is necessary to increase the module.

In our case:K = 1.14; Kbv = 1.07; ;

Yb = 3.61; K = 1.35; ; ;

.

Strength condition is satisfied.


5. ANALYSIS OF THE BEVEL GEARS FOR STRENGTH

Let us analyze the bevel gears for strength if torque at the pinion shaft Tp =460 N×m; torque at the gear shaft Tg =153 N×m velocity ratio of the gearing u =3.15; allowable contact stress [σ H ]=640 MPa; allowable bending stress [σ b ]=293 MPa, hardness of the gear material Hg =285 BHN.

5.1. Determine the external pitch diameter of the gear

,

where Tg is the torque at the gear shaft in N·mm; Etr is the transformed modulus of elasticity; KH β is the load concentration factor; u is the velocity ratio; ν H = 0.85 is the correction factor that takes into account reducing bevel gears strength in comparison with spur gears; [σ H ] is the allowable contact stress; ψ bR = bg/Re is the gear face width factor that determines proportions of the face width of the gear with respect to the external cone distance. Factor ψ bR must be less than 0.3. Recommended value of ψ bR = 0.285.

Since both pinion and gear are made of steel, the transformed modulus of elasticity Etr =2.1·105 MPa.

Load concentration factor KH β depends upon the hardness of the gear material. If Hg £350 BHN KH β is ranged from1.23 to 1.35. Otherwise (Hg >350 BHN) KH β is ranged from 1.25 to 1.45. It is necessary to note that greater values of KH β are assumed for the case when one of toothed wheels is on the cantilever shaft.

After calculation the obtained magnitude of should be rounded off to the greater side according to standard series given in table 5.1. In our case we assume =315 mm.

Table 5.1

Standard values of the external pitch diameter

Series 1                        
Series 2 - -                    

Note. Series 1 should be preferred to Series 2.

5.2. Determine pitch angles for the pinion and for the gear.

d2 = arctg u = arctg 3.15=72.38°, d1 = 90°- d2=90-72.38=17.62°.

5.3. Determine the external cone distance

.

5.4. Determine the face width of the gear

bg = × Re =0.285∙165.25=47.1 mm.

5.5. Determine the external module

,

where ν b = 0.85 is the correction factor; Kb β is the load concentration factor that is determined according to table 3.7 depending upon ψ bd factor, where the latter is found as

.

5.6. Determine the number of teeth of the gear

and round off to the integer numeral. Assume .

5.7. Determine the number of teeth of the pinion

and round off to the integer numeral too. In our case

5.8. Specify the velocity ratio of the gearing

uact = .

The error ε = should be less or equal to 4%. Otherwise, we should round off values of zp and zg to the other side.

In our case ε = =

5.9. Specify pitch angles for the pinion and the gear

d2 = arctg uact =arctg 3.12=72.23°, d1 = 90°- d2=17.77°

5.10. Determine external pitch diameters of the pinion and the gear.

, .

5.11. Determine diameters of addendum circles at the outer section for the pinion and the gear

=101.05+2∙2.35∙cos17.77°=105.53 mm, =314.91+2∙2.35∙cos72.23°=316.33 mm.

5.12. Determine diameters of dedendum circles in the outer section for the pinion and the gear.

=101.05–2.4∙2.35∙cos17.77°=95.68 mm, =314.9–2.4∙2.35∙cos72.23°=313.18 mm.

5.13. Specify the external cone distance

.

5.14. Specify the face width of the gear

=0.285∙165.36=47.28 mm.

5.15. Determine mean pitch diameters for the pinion and for the gear

, .

5.16. Determine forces that act in the engagement of the bevel gears

- turning force ;

- radial force at the gear

=3407.03∙tg20°∙cos72.23°=378.46 N;

- axial force at the gear

=3407.03∙tg20°∙sin72.23°=1180.89 N.

5.17. Determine the maximum contact stress that develops in the contact zone of teeth:

where Tp is in N·mm; KH is the design load factor determine as

KH=KH β· KHV.

Load concentration factor Kis specified by means of table 3.2 depending upon factor ψbd= .

Dynamic load factor KHV is determined according to table 3.6 depending upon the peripheral speed of the gear (Vg = ) and the accuracy of manufacturing (table 3.5). In order to use table 3.6 for bevel gears we should reduce the degree of accuracy by 1.

In our case ψ bd = , V g= m/sec. KH=KH β· KHV =1.16∙1.11=1.29.

Obtained value of σ H should correspond to the following condition

σ H =(0.8…1.1)·[σ H ]=(0.8…1.1)·640=512…704 MPa.

Otherwise it is necessary to change the external pitch diameter and recalculate the gearing. In our case strength condition is satisfied.

5.18. Determine the maximum bending stress

where Kb b is the load concentration factor that is determined by table 3.7; KbV is the dynamic load factor determined from table 3.8 (for bevel gears we should reduce the accuracy of manufacturing by 1); Yb is the tooth form factor that is determined by means of table 3.9 depending upon the number of teeth of the equivalent straight spur gear for the case when the offset factor x =0;
ν b = 0.85 is the correction factor; mm = is the mean module.



Понравилась статья? Добавь ее в закладку (CTRL+D) и не забудь поделиться с друзьями:  



double arrow
Сейчас читают про: