Electromagnets with external forward armature travel

The most widespread forms of electromagnets of this type are electromagnets, presented on fig 1.3. As it follows from pictures, in examined cases there are two identical basic air-gap, in this connection a full electromagnetic force F is determined by a formula

F = 2 F 0 = 2∙5,1 ∙B 02S 0 / μ0,

Fig. 1.3, a where В 0 − induction in a basic air-gap, Wb / сm 2; S 0 equivalence cross-section ofeach of basic gaps, сm 2.

So, MMF, being on both gaps, determined so:

(w∙I)0 = φ (w∙I)П = 2∙δ0B 0 / μ0,

where φ − coefficient, taking into account of MMF drop in steel and non-working gaps.

Induction В 0 with a glance of possible in exploitation lowering of MMF (w∙I)п = χ∙ w∙I, where χ ≤ 1, equals to: B 0 = μ0∙φ∙χ∙ w∙I / 2δ0

Permissible MMF w∙I of electromagnet coils is determined coming from its operation mode, terms of heating and presence of two coils, having a cooling surface 2 Scl.


a) Continuous running duty of Fig. 1.3, b electromagnet

For this mode next correlations, similar to got before, are correct. Resistance of one coil:

R = 10-4∙ρ∙π∙(1 + n)∙ dc∙w / 2 Sm

where w − total number of loops of both coils; Sm – cross-section of wire metal, equals to:

Sm = 2 fap∙m∙n∙ dc 2 / w.

So, general losses in resistance of electromagnet are equal to:

P = 2 R∙I 2 = 10-4∙ρ∙π (1 + n)∙ w 2 ∙I 2 / fap∙m∙n∙dc

On the other hand, Р is determined from correlation

Θper = P / 2 h∙Scl = P / [2 h∙ (Sex + α∙ Sin)].

Substituted Р and Scl from (1.5) into the formula Θ per, we will define the value of MMF of electromagnet:

w∙I = 2√[104fap∙m 2 ∙n∙ (1 + 2 n + α)∙ h∙ Θperdc 3 / ρ(1 + n)]

the value of electromagnetic force

F = 8∙104∙μ0∙φ2∙ε2∙χ2fap ∙τ2m 2n ∙(1+ 2 n + α)∙ h∙ Θperdc 5/ [ρ(1 + n) δ02],

and key size of a core

dс = 5√{[103∙ρ∙(1 + n)∙ F∙ δ02 / [φ2∙ε2∙χ2fap ∙τ2m 2n ∙(1+ 2 n + α)∙ h∙ Θper]}

Designating, as well as before,

C 1 = [2∙103∙ρ(1+ n)] / [φ2∙χ2 ∙fap τ2 ∙m 2 ∙n∙ (1+2 n +α)∙ h∙ Θ per ], we will get accordingly:

F =2dc 5 / (C 1∙ δ02) (1.42)

and dc = 5 [ C 1F ∙δ02 / 2ε2] (1.43)

Transformation of the last formula gives dependence

F / δ03 = 2ε2∙χ5 / C 1, (1.44)

facilitating, as it was explained before, determination of dc = χ∙δ0. Thus under F they understand full force of electromagnet. In this case we determine:

1) MMF of coils

w∙I = (9∙103dc / φ∙χ∙τ)∙√(dc / C 1) (1.45)

2) cross-section of wire

Sm = [2.82∙ρ∙(1 + n)∙ dc 2 / (φ∙χ∙τ∙ U)]∙√(dc / C 1) (1.46)

3) number of coil loops

w = U∙√ [103fap∙n / ρ∙(1 + n)∙(1 + 2 n + α)∙ h∙ Θ perdc)] = C 2 ∙U∙√ (C 1 /dc) (1.47)

4) induction in a working air-gap

B 0 = (0,396∙10-4F) / (τ∙ε∙ dc)

approximately by a formula

B 0 (4∙10-5 / τ∙ 5C 1)∙√(F 3/ δ04)

b) Recursive short-time mode

Conclusions, similar to given above, determine next correlations for the electromagnets of this type:

F = 2 p 2 cr∙ε 2 ∙d 5 c / (C 1 δ02) (1.48) dc = 5 [ C 1 ∙F∙ δ02 / (2 p 2 cr∙ε 2)] (1.49)

F / δ03 = 2 p 2 cr∙ε 2χ5 / C 1(1.50)

w∙I = (9∙103pcrdc / φ∙χ∙τ)∙√(dc / C 1) (1.51)

Sm = [2.82∙ρ∙(1 + n)∙ pcrdc 2 / (φ∙χ∙τ∙ U)]∙√(dc / C 1) (1.52)

w = (U/ pcr) ∙√ {103fap∙n / [ρ∙(1 + n)∙(1 + 2 n + α)∙ h∙ Θ perdc)]}(1.53)

The coefficient of overcurrent pcr can be defined under the set size of relative duty ratio DR %: pcr = √100 / DR %.

c) Short-time duty

In this mode, ignoring heat emission from a surface, they accept, that all radiated heat in a coil goes to heating of active material. For electromagnets with externalforward armature travel and two coils it is got a like § 1.1:

permissible current density in the cross-section of wire


j = I / Sm = w∙I / (2 fap∙m∙n∙d 2 c),

MMF of electromagnet


w∙I = 2 fap∙m∙n∙j∙d 2 c,

induction in a basic air-gap

B 0 = μ0 φ∙χ ∙ w∙I /0,

full electromagnetic force

F = 5,1π∙μ0 φ2∙χ2 ∙j 2 ∙f 2 ap∙m 2 ∙n 2 ∙ε 2 ∙τ 2 ∙d 6 c / δ02.

If to enter denotation

C3 = √[2∙103∙ρ / c∙ γ m ∙Θper φ2∙χ2 ∙f 2 ap∙m 2 ∙n 2 ∙τ 2] ≈ 0,14 / (φ∙χ ∙fap∙m∙n∙τ), (1.54)

that we will get

F = 2 ε 2 ∙d 6 c / C 23 δ02ton.. (1.55)

The key size of examined electromagnetic core in short-time duty is determined by a formula

dc = 3 [(C 3∙ δ0 / 1,41∙ε)∙√(F∙ton) (1.56)

Dependence of F = F (χ) is determined by correlation

F / δ02 = 1,41∙ε∙ x 3 / (C 3∙√ ton) (1.57)

from which it is determined by a method, considered before:

dc = χ∙ δ0

and accordingly cross-section of wire metal

Sm = ρ∙(1 + n)∙ fap∙m∙n∙d 3 c / (U∙ton)

and number of loops of two coils

w = U∙ C4∙√ ton / dcU∙ton / (π ρ∙(1 + n)∙ dc) (1.58)

Induction in a working air-gap is calculated under the found values of dc, χ, ε or approximately by a formula:

B 0 (3,8∙10-5 / τ∙ 3C 3)∙ 3√[ F /0∙√ ton)]



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