Table 11.1

Values of X, Y and e for some types of bearings

Type of bearing Fa/C o Fa/ (VFre Fa /(VFr)> e e
X Y X Y
Single Row radial Ball Bearing   0.014     0.56 2.30 0.19
0.028 1.99 0.22
0.056 1.71 0.26
0.084 1.55 0.28
0.11 1.45 1.30
0.17 1.31 0.34
0.28 1.15 0.38
0.42 1.04 0.42
0.56 1.00 0.44
Single Row Angular Contact Ball Bearing   0.014     0.45 1.81 0.30
0.029 1.62 0.34
0.057 1.46 0.37
0.086 1.34 0.41
0.11 1.22 0.45
0.17 1.13 0.48
0.29 1.14 0.52
0.43 1.01 0.54
0.57 1.00 0.54
      0.41 0.87 0.68
      0.37 0.66 0.95
Single row Tapered Roller Bearing       0.4 0.4ctga 1.5ctga

11.2.3. Determine total axial forces Fa 1 and Fa 2. For that we should find the sum Fa + S 1 and compare with force S 2. There are 3 possible cases:

– if Fa + S 1 > S 2 Fa 1 = S 1 and Fa 2 = Fa + S 1;

– if Fa + S 1 = S 2 Fa 1 = S 1 and Fa 2 = S 2;

– if Fa + S 1< S 2 Fa 1 = S 2 Fa and Fa 2 = S 2.

In our case Fa + S 1 = 346.7 +2247.5 = 2594.2 N < S 2 = 2961.1 N, therefore Fa 1 = 2961.1 – 346.7 = 2614.4 N and Fa 2 = 2961.1 N.

11.3. Determine factor V that takes into account what ring of the bearing is movable.

– for bearings with movable inner ring V = 1;

– for bearings with movable outer ring V = 1.2.

In general purpose speed reducers bearings with movable inner ring are used only.

11.4. Determine safety factor Ks that takes into account the load nature. It may be ranged from 1 to 2.5 depending upon the type of designing machine. For general purpose speed reducers the safety factor is assumed as 1.3.

11.5. Determine temperature factor Kt according to table 11.2.


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